Given a mounted display with a diagonal of 42 inches and a height of 20.6 inches, how wide is the display?

To determine the width of a mounted display given its diagonal measurement and height, we can utilize the properties of a right triangle formed by the width, height, and diagonal (hypotenuse). The diagonal serves as the hypotenuse of the triangle, with the height and width being the two other sides.

Using the Pythagorean theorem, we can express the relationship as follows:

Width² + Height² = Diagonal²

First, convert the given diagonal from inches to the same unit (which is already in inches), assigning the values:

• Diagonal = 42 inches

• Height = 20.6 inches

Substituting these values into the equation gives us:

Width² + (20.6)² = (42)²

Calculating (20.6)² results in approximately 424.36, and (42)² equals 1764.

This simplifies to:

Width² + 424.36 = 1764

Now, isolate Width²:

Width² = 1764 - 424.36

Width² ≈ 1339.64

Taking the square root of both sides provides:

Width ≈ √1339.64 ≈ 36.6 inches

However