What is the impedance of a circuit with two 8 ohm loudspeakers and one 4 ohm loudspeaker wired in parallel?

To determine the impedance of a circuit with multiple speakers connected in parallel, you can use the formula for combined impedance in parallel circuits. The formula for total impedance (Z) in a parallel circuit with multiple resistors (or speakers, in this case) is given by:

1/Z = 1/Z1 + 1/Z2 + 1/Z3 + ...

In this scenario, you have two 8-ohm loudspeakers and one 4-ohm loudspeaker. Applying the formula:

1/Z = 1/8 + 1/8 + 1/4

First, convert each term to a common denominator, which is 8:

1/Z = 1/8 + 1/8 + 2/8

1/Z = 4/8

Z = 8/4

Z = 2 ohms

It appears there was a miscalculation in getting to the answer of 4 ohms. That value would suggest a specific arrangement or different calculations that aren't consistent here. The real determination shows that when the total combined impedance of these speakers is calculated properly, it equals 2 ohms.

Hence, the proper assessment of the impedance of this specific configuration reflects that the total impedance is indeed