When two identical loudspeakers are wired in parallel, how does the total impedance compare to one of the loudspeakers?

When two identical loudspeakers are wired in parallel, the total impedance decreases compared to the impedance of one of the individual loudspeakers. The reason for this lies in the formula used to calculate the total impedance in a parallel circuit.

For two identical impedances (Z) connected in parallel, the total impedance (Z_total) can be calculated using the formula:

Z_total = Z / n

where n is the number of speakers connected in parallel. In this case, since there are two speakers, n equals 2. Therefore:

Z_total = Z / 2

This means that the total impedance is half of the impedance of one loudspeaker. As a result, the total impedance is indeed lower than that of a single loudspeaker, which confirms the correctness of the answer.

This decrease in impedance effectively allows more current to flow through the loudspeakers, potentially increasing the overall sound output depending on the amplifier's characteristics and how it can handle that lower impedance load.